EC 311 - Intermediate Microeconomics
2025
Outline
Topics
Optimal Consumption (4.4)
Slopes Logic
Constrained Optimization
So far we have done 3 things:
Now we will put it all together to solve problems
We will do it by:
Solving it graphically to gain the intuition of what is happening
Mathematically, because we need to be able to solve these problems formally
The core question we are attempting to answer is
Given a specific budget constraint, what bundle should an individual choose to maximize their utility?
These are our two ingredients to solving a utility maximization problem
The key for these graphs is to internalize the fact that there are infinite amounts of IC we can draw
And only one will be utility maximizing bundle
Which one is the utility maximizing bundle?
Point A
Affordable and on the Budget Line
Point B
Affordable but does not use all our budget
Point C
Affordable and on the Budget Line
Point D
Highest utility but unaffordable
Point C is the highest level of indifference curve that is on the budget line only once!
ICs above the BC:
ICs below the BC:
Point C is a magical point
It is where the IC touches the BC exactly once
Every other point on the green IC is unaffordable
We call Point C the Utility Maximizing Bundle
Moving along the BC, to other affordable bundles like Point A only makes you worse off
But what is so special about Point C? Math does!
This is the point where the BC line and the IC curve have the exact same slope, this is also known as the point where they are tangent
This helps us put the intuition we gained from the graph together with the math
The key to finding the utility maximizing bundle (the best mix of \(x\) and \(y\)) you have to find the bundle where the BC and IC have the same slope
Let’s recall what the Slope of the IC means:
It is the Negative MRS
It tells you how much \(y\) you would be willing to give up to get another unit of \(x\)?
Now recall what the Slope of the BC means:
It is the Negative Price Ratio
It tells you how much \(y\) you would have to give up to get another unit of \(x\)?
Imagine what it would it mean if these two slopes were not equal
You are consuming Bundle A where:
The Negative MRS is \(-4\)
What does this mean?
Let’s also say that the Negative Price Ratio is \(-3\)
What does this mean?
Because it is “cheaper” to trade \(y\) for \(x\) than you are willing to, you will make the trade
Is this a utility maximizing bundle? Why or Why not?
If \(\text{Negative MRS } \neq \text{ Price Ratio}\) then you trade that bundle for another, which means that you were not at a utility maximizing bundle
The logic here is:
Let’s draw it!
If \(\text{Negative MRS } < \text{ Price Ratio}\) (Point A)
Graphically, this means that the IC is steeper than the BC
Trading away some \(y\) for some \(x\) moves you down and to the right in the better-than set
If \(\text{Negative MRS } > \text{ Price Ratio}\) (Point B)
Graphically, this means that the IC is flatter than the BC
Trading away some \(x\) for some \(y\) moves you up and to the left in the better-than set
The graph implicitly says:
There are an infinite number of ICs that all correspond to different levels of utility
There is only one BC
Utility maximization happens only when you find the point on the BC that touches the highest possible IC (once)
The logic takaways here are:
When you have a curved IC, you have to set the slope of the IC equal to the slope of the BC to find the utility-maximizing bundle
If they are not equal, you would be willing to make some trade to a different bundle
The magical point of maximization only occurs if the ICs are Non-Crossing, Monotonic, and Convex
Most importantly, there is only one magical point
We know the steps:
Calculate the MRS of a given utility function
Calculate the Price Ratio using the Budget Constraint
Set them equal to each other
It really is this simple, but the math makes it look more complicated
The problem will take the form of
\[\max \; U(x,y) \;\;\;\; \text{subject to} \;\;\;\; P_{x} \cdot x + P_{y} \cdot y = M\]
This is what we call a Constrained Optimization problem
We had four different forms that utility can take:
Cobb-Douglas
Quasi-linear
Perfect Substitutes
Perfect Complements
Each have their quirks and procedure to follow
Solving these type of problems is the crux of the course. I know it can be intimidating at first glance, but my personal advice is to not over think the process, that’s what the steps are for
The theory is what will guide you and allow you to interpret results, and it may seem wonky at first but that’s just how economists think
There is a 4-step approach that we will follow to solve these problems when the utility function is Cobb-Douglas
Calculate the MRS and set it equal to the Price Ratio
Re-arrange this equality to isolate one good (\(x\) or \(y\)) as a function of the other (It does not matter which good you choose here).
Write down your budget constraint and plug the optimality condition into it.
Use your demand for one good and plug it into either the optimality condition or the BC to find the demand for the other good
\[\text{Let } \, U(x,y) = xy, \; P_{x} = 1, \; P_{y} = 2, \; M = 12\]
Find MRS
\[MRS = \dfrac{MU_{x}}{MU_{y}} = \dfrac{y}{x}\]
Find Price Ratio
\[\text{Price Ratio} = \dfrac{P_{x}}{P_{y}} = \dfrac{1}{2}\]
Set them equal to each other
\[\dfrac{y}{x} = \dfrac{1}{2}\]
\[\dfrac{y}{x} = \dfrac{1}{2}\]
You can isolate either \(x\) or \(y\)
Isolating \(y\)
\[y = \dfrac{x}{2}\]
Isolating \(x\)
\[x = 2y\]
These are optimality conditions for \(x\) and \(y\)
They tell us the demand of a good conditional on other model parameters
\[y = \dfrac{x}{2} \;\; \& \;\; BC: \, x + 2y = 12\]
Here I will plug in my known value of \(y\) anywhere I find a \(y\) in the BC
\[\begin{align*} x + 2y &= 12 \\ x + 2(\dfrac{x}{2}) &= 12 \\ x + x &= 12 \\ 2x &= 12 \\ x^{*} &= 6 \end{align*}\]
Note: I will denote the optimal amount for any good as \(x^{*}\) or \(y^{*}\) or whatever variable the problem uses
\[\text{We found that } x^{*} = 6\]
I’ll do it both ways just to show you that it works but you only have to do one (I recommend finding which one is simpler for you)
Plugging into Optimality Condition
\[\begin{align*} y &= \dfrac{x^{*}}{2} \\ y &= \dfrac{6}{2} \\ y^{*} &= 3 \end{align*}\]
Plugging into Budget Constraint
\[\begin{align*} x^{*} + 2y &= 12 \\ 6 + 2y^{*} &= 12 \\ 2y^{*} &= 6 \\ y^{*} &= 3 \end{align*}\]
Lastly, in exams I will expect the answers to be identified at the end of your work so I know you actually answered the question that was asked
\[U(x,y) = x^{1/4}y^{3/4}, \; P_{x} = 2, \; P_{y} = 3, \; M = 32\]
What are the optimal amounts of \(x\) and \(y\) to maximize this individual’s utility subject to their budget constraint?
\[x^{*} = 4 \; \& \; y^{*} = 8\]
What utility level \(U^{*}\) is achieved?
\[U^{*} = (x^{*})^{1/4} (y^{*})^{3/4} = (4)^{1/4} (8)^{3/4} = \ldots\]
\[MRS = \dfrac{MU_{x}}{MU_{y}} = \dfrac{1/4 \, x^{-3/4} y^{3/4}}{3/4 \, x^{1/4} y^{-1/4}} = \dfrac{1/4}{3/4} \cdot \dfrac{y^{3/4} y^{1/4}}{x^{1/4} x^{3/4}} = \dfrac{1}{3} \cdot \dfrac{y}{x}\]
Also recall:
\[MRS = \dfrac{a}{b} \cdot \dfrac{y}{x} = \dfrac{1/4}{3/4} \cdot \dfrac{y}{x} = \dfrac{1}{3} \cdot \dfrac{y}{x}\]
\[\text{Price Ratio} = \dfrac{P_{x}}{P_{y}} = \dfrac{2}{3}\]
\[\dfrac{y}{3x} = \dfrac{2}{3} \; \rightarrow \; y = 2x\]
Plug optimailty condition into BC
\[\begin{align*} \text{BC: } 2x + 3y &= 32 \\ 2x + 3(2x) &= 32 \\ 8x &= 32 \\ x^{*} &= 4 \end{align*}\]
Find demand for \(y\)
\[\begin{align*} y^{*} &= 2x^{*} \\ y^{*} &= 2(4) \\ y^{*} &= 8 \end{align*}\]
To solve problems with this utility functional form we repeat the same steps as C-D but we skip step 3
Find the MRS and set it equal to the Price Ratio
Solve the equality for the non-linear good (usually inside the \(ln()\))
Use the BC to find the demand of the other good
\[\text{Let } \, U(x,y) = 10 \cdot ln(x) + \dfrac{y}{2}, \; P_{x} = 5, \; P_{y} = 2, \; M = 70\]
Find MRS
\[MRS = \dfrac{MU_{x}}{MU_{y}} = \dfrac{10/x}{1/2} = \dfrac{20}{x}\]
Find Price Ratio
\[\text{Price Ratio} = \dfrac{P_{x}}{P_{y}} = \dfrac{5}{2}\]
Set them equal to each other
\[\dfrac{20}{x} = \dfrac{5}{2}\]
\[\dfrac{20}{x} = \dfrac{5}{2}\]
We solve for x (notice there is no \(y\))
\[\begin{align*} 40 &= 5x \\ x^{*} &= 8 \end{align*}\]
\[\text{BC: } 5x + 2y = 70, \;\; x^{*} = 8\]
\[\begin{align*} 5x^{*} + 2y &= 70 \\ 5(8) + 2y &= 70 \\ 40 + 2y &= 70 \\ 2y &= 70 \\ y^{*} &= 35 \end{align*}\]
Recall the functional form
\[U(x,y) = ax + by\]
Mathematically, the MRS will just equal a constant \(\left(\dfrac{a}{b} \right)\) so setting it equal to the price ratio doesn’t really do much
It will either be larger than, smaller than, or equal
So what do we do? A graph will help us see
\[\text{Let } U(x,y) = x + y, \; P_{x} = 10, \; P_{y} = 18, \; M = 90\]
Find the MRS
\[MRS = \dfrac{1}{1} = 1\]
Find Price Ratio
\[\dfrac{P_{x}}{P_{y}} = \dfrac{10}{18} = \dfrac{5}{9}\]
Graph
Here, the individual chooses to only consume good \(x\) and no \(y\). Why?
The ICs are steeper than the BC
The intuition is saying that the willingness to trade \(y\) for \(x\) is always larger than the ability to trade
This individual will get all the \(x\) they can!
\[U(x,y) = 2x + 3y, \; P_{x} = 1, \; P_{y} = 1/2, \; M = 5\]
Find the MRS
\[MRS = \dfrac{2}{2} = 1\]
Find Price Ratio
\[\dfrac{P_{x}}{P_{y}} = \dfrac{1}{1/2} = 2\]
Graph
As we saw, maximization problems with P-Subs functional form have two predictable outcomes
Either you consume all \(x\) and no \(y\) or all \(y\) and no \(x\)
There is the unusual case where the slopes are the same
Graphically, this means that they will perfectly overlap
Mathematically, any bundle that meets the requirements will work
The graphs we just saw tell us how to do the math:
Find the MRS and Price Ratio
Compare the MRS to the Price Ratio
Figure out how much \(x\) and \(y\) to consume using the BC
\[U(x,y) = 3x + 2y, \; P_{x} = 1, \; P_{y} = 4, \; M = 60\]
Find MRS and Price Ratio
\[\begin{align*} MRS &= \dfrac{MU_{x}}{MU_{y}} = \dfrac{3}{2} \\ \text{Price Ratio} &= \dfrac{P_{x}}{P_{y}} = \dfrac{1}{4} \end{align*}\]
Compare MRS to Price ratio
\[\begin{align*} \dfrac{3}{2} &> \dfrac{1}{4} \\ \text{MRS} &> \text{Price Ratio} \end{align*}\]
Choose only \(x\)
Figure out how much \(x\) and \(y\) to consume using the BC
\[\begin{align*} \text{BC: } x + 4y &= 60 \\ x + 4(0) &= 60 \\ x^{*} &= 60 \\ y^{*} &= 0 \end{align*}\]
With Perfect Substitutes the goods do not interact at all
So the question really becomes:
When you say that the MRS is less than the Price Ratio, you are also saying that you get fewer units of utility per dollar spent on \(x\) than per dollar spent on \(y\). Therefore, you should only consume \(y\).
Note: This logic only works for Perfect Substitutes. This is because the MRS is always a constant
Recall: We cannot solve this utility form like the others because there is no MRS
So let’s see what a graph can tell us
\[U(x,y) = \min \{2x,3y\}, \; P_{x} = 2, \; P_{y} = 2, \; M = 40 \]
Point C is the minimum point of this indifference curve but is it maximizing?
Hidden Point D is the actual maximizing point
Remember that there are is always a Better-Than Set where other ICs exist
The bundles on both the IC and the BC involve “wasting” one good or the other
Recall that the “No-Waste Condition” says that you should achieve a certain utility level with the minimum units of \(x\) and \(y\) possible
The previous graph showed us that Point D is the utility maximizing point, now let’s learn how to find it
I will be bold and say that this is one of the simpler utility functions to maximize
Just be sure to follow the steps:
Solve the “No-Waste Condition” for one of the goods (Does not matter which one)
Plug the optimality condition into the budget constraint and find the demand of one Good
Use either the BC or the “No-Waste Condition” to solve for the demand of the other good
\[U(x,y) = \min \{\dfrac{x}{2}, 2y\}, \; P_{x} = 1, \; P_{y} = 3, \; M = 56\]
Solve the No-Waste Condition
Solving for \(x^{*}\)
\[\begin{align*} \dfrac{x}{2} &= 2y \\ x^{*} &= 4y \end{align*}\]
Solving for \(y^{*}\)
\[\begin{align*} \dfrac{x}{2} &= 2y \\ y^{*} &= \dfrac{x}{4} \end{align*}\]
\[x^{*} = 4y \; \text{or} \; y^{*} = \dfrac{x}{4} \;\; , \;\; \text{BC: } x + 3y = 56\]
\[\begin{align*} x + 3y &= 56 \\ (4y) + 3y &= 56 \\ 7y &= 56 \\ y^{*} &= 8 \end{align*}\]
\[y^{*} = 8 \;\; \text{and} \;\; \text{No-Waste Condition: } \dfrac{x}{2} = 2y\]
\[\begin{align*} \dfrac{x}{2} &= 2y \\ x^{*} &= 4y \\ x^{*} &= 4(8) \\ x^{*} &= 32 \end{align*}\]
So our optimal bundle is:
\[x^{*} = 32 \;\; \& \;\; y^{*} = 8\]
This lecture has taught you how to solve the 4 different utility functional forms constrained maximization problems graphically and mathematically
With this in our toolbox, we can find the individual demand of goods.
The next step is to find Demand Functions for the entire market
EC311 - Lecture 04 | Utility Maximization